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ExamsJN0-102Questions#25
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JN0-102 · Question #25

JN0-102 Question #25: Real Exam Question with Answer & Explanation

The correct answer is B. 14. To calculate the number of usable host addresses in a /28 network, determine the total addresses from the host bits and subtract two for the network and broadcast addresses.

Routing Fundamentals

Question

How many host addresses are available in the /28 network?

Options

  • A6
  • B14
  • C28
  • D30

Explanation

To calculate the number of usable host addresses in a /28 network, determine the total addresses from the host bits and subtract two for the network and broadcast addresses.

Common mistakes.

  • A. 6 is an incorrect calculation; it would correspond to a /29 network (2^3 - 2 = 6).
  • C. 28 represents the CIDR prefix length, not the number of available host addresses.
  • D. 30 is incorrect; it corresponds to a /27 network (2^5 - 2 = 30).

Concept tested. IPv4 subnetting host address calculation

Reference. https://docs.microsoft.com/en-us/troubleshoot/windows-server/networking/understand-tcpip-addressing-and-subnetting-basics

Topics

#subnetting#host addresses#CIDR#network calculation

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