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JN0-102 · Question #23

What is the network address for the 10.13.147.100/19 host?

The correct answer is A. 10.13.128.0. To find the network address for a given host and subnet mask, apply the subnet mask to the host IP address (bitwise AND operation). For a /19 mask, the relevant calculation occurs in the third octet.

Routing Fundamentals

Question

What is the network address for the 10.13.147.100/19 host?

Options

  • A10.13.128.0
  • B10.13.147.0
  • C10.13.0.0
  • D10.13.100.0

How the community answered

(29 responses)
  • A
    83% (24)
  • B
    3% (1)
  • C
    10% (3)
  • D
    3% (1)

Why each option

To find the network address for a given host and subnet mask, apply the subnet mask to the host IP address (bitwise AND operation). For a /19 mask, the relevant calculation occurs in the third octet.

A10.13.128.0Correct

A /19 subnet mask is 255.255.224.0. Applying this mask to 10.13.147.100, the first two octets remain 10.13. The third octet's calculation is 147 (10010011 binary) AND 224 (11100000 binary), which results in 128 (10000000 binary). The fourth octet becomes 0. Thus, the network address is 10.13.128.0.

B10.13.147.0

10.13.147.0 is not the network address; 147 is the host's third octet, not the network's.

C10.13.0.0

10.13.0.0 would be the network address for a /16 or larger prefix.

D10.13.100.0

10.13.100.0 is an arbitrary address not derived from the /19 mask applied to 10.13.147.100.

Concept tested: Subnetting - network address calculation

Topics

#subnetting#network address#IPv4 addressing#CIDR

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