HP
HP0-S34 · Question #66
A customer has 30 hard drives in a RAID 60 with five parity groups. How many drives can simultaneously fail in the array without data loss?
The correct answer is C. 10. 30 Disk / 5 parity/raid group = 6 Disk per parity Group Raid 6= n+2Parity So 10 Disk is the Answer 2 Parity Disk / group 5 groups = 25=10
Storage Configuration and RAID Implementation
Question
A customer has 30 hard drives in a RAID 60 with five parity groups. How many drives can simultaneously fail in the array without data loss?
Options
- A2
- B6
- C10
- D12
How the community answered
(17 responses)- A12% (2)
- B6% (1)
- C76% (13)
- D6% (1)
Explanation
30 Disk / 5 parity/raid group = 6 Disk per parity Group Raid 6= n+2Parity So 10 Disk is the Answer 2 Parity Disk / group * 5 groups = 2*5=10
Topics
#RAID 60#parity groups#fault tolerance#simultaneous drive failure
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