HP
HP0-S34 · Question #1
A customer has 30 HD drives in a RAID 60 with five parity groups. How many drives can simultaneously fail in the array?
The correct answer is C. 10. 30 Disk / 5 parity/raid group = 6 Disk per parity Group Raid 6= n+2Parity So 10 Disk is the 2 Parity Disk / group 5 groups = 25=10
Storage and Network Integration in Server Solutions
Question
A customer has 30 HD drives in a RAID 60 with five parity groups. How many drives can simultaneously fail in the array?
Options
- A2
- B6
- C10
- D12
How the community answered
(40 responses)- A5% (2)
- B8% (3)
- C73% (29)
- D15% (6)
Explanation
30 Disk / 5 parity/raid group = 6 Disk per parity Group Raid 6= n+2Parity So 10 Disk is the 2 Parity Disk / group * 5 groups = 2*5=10
Topics
#RAID 60#parity groups#drive failure tolerance#RAID math
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