H13-311_V3.5 · Question #56
X, Y are random variables, C is a constant, the nature of the difference in the following options which is wrong? (Multiple choice)
The correct answer is B. D(X+ Y)=D(X)+D(Y) D. D(XY)=D(X)D{Y). Options B and D are wrong because they state equalities that only hold under special conditions, not in general. D(X+Y) = D(X) + D(Y) is only valid when X and Y are independent (or at least uncorrelated); the correct general formula is D(X+Y) = D(X) + D(Y) + 2Cov(X,Y), where…
Question
X, Y are random variables, C is a constant, the nature of the difference in the following options which is wrong? (Multiple choice)
Options
- AD(C)=O
- BD(X+ Y)=D(X)+D(Y)
- CD(CX)=C'C'D()()
- DD(XY)=D(X)D{Y)
How the community answered
(51 responses)- A10% (5)
- B73% (37)
- C18% (9)
Explanation
Options B and D are wrong because they state equalities that only hold under special conditions, not in general. D(X+Y) = D(X) + D(Y) is only valid when X and Y are independent (or at least uncorrelated); the correct general formula is D(X+Y) = D(X) + D(Y) + 2Cov(X,Y), where the covariance term is omitted in B. D(XY) = D(X)D(Y) has no general validity at all - the variance of a product involves higher-order moments and does not factor this cleanly under any standard condition. Options A and C are correct: D(C) = 0 because a constant has no variability, and D(CX) = C²D(X) because the constant scales deviations and variance squares that scaling factor.
Memory tip: For variance, constants kill spread (A), scalar multiplication squares (C), and anything involving sums or products of two random variables requires checking independence - if independence is not given, formulas B and D both fail.
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