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H12-811_V1.0 · Question #133

The protocol uses the P/A mechanism to speed up the upstream port's transition to the Forwarding state, but what is the reason for no temporary loop? ()

The correct answer is A. Ensure that there will be no temporary loops through the synchronization mechanism. See the full explanation below for the reasoning.

Question

The protocol uses the P/A mechanism to speed up the upstream port's transition to the Forwarding state, but what is the reason for no temporary loop? ()

Options

  • AEnsure that there will be no temporary loops through the synchronization mechanism
  • BSpeed up port role election
  • CReduced the time of ForwarD.Delay
  • DEdge port

How the community answered

(34 responses)
  • A
    71% (24)
  • B
    18% (6)
  • C
    9% (3)
  • D
    3% (1)

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