In the dual-link backup technology, which of the following descriptions about the master-slave AC election is correct? (Multiple choice)

Question

Options

• AIn the case of the same load, compare the IP addresses, and the one with the larger l address is
• BCompare the priority of the AC, the one with the higher priority value is the master AC
• CPrioritize the selection of the AC with the largest number of currently accessible APs as the main
• DIn the case of the same priority, compare the load of AC equipment, that is, the number of A and

• A
  12% (5)
• B
  5% (2)
• C
  84% (36)

Explanation

In dual-link backup, the master AC election follows a sequential tie-breaking process. Option C is correct because the primary election criterion is AP accessibility - the AC currently managing the most online APs is elected master, ensuring service continuity is prioritized. Option D is correct because when ACs share the same priority, the tiebreaker is load (number of managed APs), again favoring the AC handling more traffic.

Option B is wrong because priority alone does not decide the master - the number of accessible APs is evaluated first; priority is a secondary criterion, not the leading one. Option A is wrong because IP address comparison is the last resort tiebreaker (after both AP count and priority are equal), not triggered by equal load alone - and the incomplete/misordered condition makes the statement inaccurate.

Memory tip: Think of the election as a job interview ranking - first pick the candidate already serving the most users (most accessible APs → C), then check seniority (priority), then workload capacity (load → D), and only as a last resort use an arbitrary identifier (IP address). "Serve first, rank second, load third, IP last."

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