If IP phone A and analog phone B directly register with the same U1960 unified gateway, which of the following statements is CORRECT?

Question

Options

• AMedia streams of A and B do not need to pass through U1960.
• BIf A and B are engaged in a call, the signaling path is different from the media path.
• CWhen A and B are engaged in a call and U1960 encounters an unexpected power failure, the call
• DAfter U1960 is powered off, A and B cannot initiate new calls.

• A
  5% (3)
• B
  4% (2)
• C
  13% (7)
• D
  78% (43)

Explanation

Option D is correct because the U1960 acts as the central registrar and call-routing engine for both phones. When it powers off, IP Phone A loses its SIP registration point and cannot route calls, while Analog Phone B - physically connected via an FXS port - loses its only interface to the network entirely.

Why the distractors are wrong:

• A is wrong because Analog Phone B is physically terminated on U1960's FXS port, so U1960 must transcode between analog and IP - media must pass through it.
• B is wrong because both signaling and media travel through U1960 in this topology; there is no separate peer-to-peer media path when an FXS-connected analog phone is one of the endpoints.
• C is wrong (despite being cut off in the text) because a power failure on U1960 would drop any active call - the analog phone's media stream is terminated on the gateway itself, so power loss kills the connection immediately.

Memory tip: Think of U1960 as the "switchboard" - the analog phone is physically plugged into it like an old telephone exchange, and the IP phone depends on it as its registrar. If the switchboard goes dark, nobody can make a call, and ongoing calls drop instantly.

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