DVA-C02 · Question #744
Given the source code for an AWS Lambda function in the local file store.py containing a handler function called get_store and the following AWS CloudFormation template: What should be done to…
The correct answer is B. Use aws cloudformation package to upload the source code to an Amazon S3 bucket and. The AWS SAM (Serverless Application Model) template shown uses Transform: AWS::Serverless-2016-10-31, which requires preparing the Lambda source code for deployment using the command: aws cloudformation package --template-file template.yaml --s3-bucket YOUR_BUCKET_NAME…
Question
Given the source code for an AWS Lambda function in the local file store.py containing a handler function called get_store and the following AWS CloudFormation template:
What should be done to prepare the template so that it can be deployed using the AWS CLI command aws cloudformation deploy?
Exhibits
Options
- AUse aws cloudformation compile to base64 encode and embed the source file into a modified
- BUse aws cloudformation package to upload the source code to an Amazon S3 bucket and
- CUse aws lambda zip to package the source file together with the CloudFormation template and
- DUse aws server less create-package to embed the source file directly into the existing
How the community answered
(31 responses)- A6% (2)
- B77% (24)
- C13% (4)
- D3% (1)
Explanation
The AWS SAM (Serverless Application Model) template shown uses Transform: AWS::Serverless-2016-10-31, which requires preparing the Lambda source code for deployment using the command: aws cloudformation package --template-file template.yaml --s3-bucket YOUR_BUCKET_NAME -- output-template-file packaged.yaml This command uploads the source code (e.g., store.py) to an S3 bucket and replaces the CodeUri in the template with a reference to the S3 location, producing a modified CloudFormation template that can then be deployed using aws cloudformation deploy.
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