DEA-1TT5 · Question #3
A company plans to deploy a new application in their environment. The new application requires 2 TB of storage space. During peak workloads, the application is expected to generate 4500 IOPS with a…
The correct answer is C. 50. 4500iops/90iops = 50 disks 50250GB = 12500 gb (12500gb 0.7)/1000 = 8.75 TB which is > 2 TB , utilization is 2/12.5 * 100(%) = 16% os is < 70%
Question
A company plans to deploy a new application in their environment. The new application requires 2 TB of storage space. During peak workloads, the application is expected to generate 4500 IOPS with a typical I/O size of 4 KB. The capacity of each available disk drive is 250 GB. In addition, the maximum number of IOPS a drive can perform at with a 70% utilization is 90 IOPS. What is the minimum number of disk drives needed to meet the application's capacity and performance requirements for a RAID 0 configuration?
Options
- A8
- B40
- C50
- D70
How the community answered
(39 responses)- A15% (6)
- B5% (2)
- C69% (27)
- D10% (4)
Explanation
4500iops/90iops = 50 disks 50*250GB = 12500 gb (12500gb * 0.7)/1000 = 8.75 TB which is > 2 TB , utilization is 2/12.5 * 100(%) = 16% os is < 70%
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