An 802.11 WLAN transmitter that emits a 50 mW signal is connected to a cable with 3 dB of loss. The cable is connected to an antenna with 16 dBi of gain. What is the power level at the Intentional…

Question

Options

• A25 mW
• B250 mW
• C500 mW
• D1000 mW

• A
  11% (5)
• B
  25% (11)
• C
  5% (2)
• D
  59% (26)

Explanation

The power level at the Intentional Radiator (IR) is 250 mW. The IR is the point where the RF signal leaves the transmitter and enters the antenna system. To calculate the power level at the IR, we need to consider the output power level of the transmitter, the loss of the cable, and the gain of the antenna. The formula is: Power level at IR (dBm) = Output power level (dBm) - Cable loss (dB) + Antenna gain (dBi) We can convert the output power level of 50 mW to dBm by using the formula: Power level (dBm) = 10 * log10(Power level (mW)) Therefore, 50 mW = 10 * log10(50) = 16.99 dBm We can plug in the values into the formula: Power level at IR (dBm) = 16.99 - 3 + 16 = 29.99 dBm We can convert the power level at IR from dBm to mW by using the inverse formula: Power level (mW) = 10^(Power level (dBm) / 10) Therefore, 29.99 dBm = 10^(29.99 / 10) = 999.96 mW However, since we need to round off the answer to the nearest integer value, we get: Power level at IR (mW) = 1000 mW

No community discussion yet for this question.