How many test cases are needed to test code fragment lines 26 - 32 to achieve 100% multiple condition coverage? 2 credits [K3]

Question

Options

• A2
• B3
• C4
• D8

• A
  17% (4)
• B
  8% (2)
• C
  4% (1)
• D
  71% (17)

Explanation

Multiple Condition Coverage (MCC) requires testing every possible combination of truth values for all atomic (individual) boolean conditions in a decision. The formula is 2^N, where N is the number of atomic conditions.

The code in lines 26–32 contains 3 atomic conditions, so 2^3 = 8 test cases are required to cover all combinations (TTT, TTF, TFT, TFF, FTT, FTF, FFT, FFF) - making D correct.

• A (2) is wrong - 2 test cases would only satisfy branch/decision coverage (true/false) for a single condition, or MCC for just 1 condition (2^1 = 2).
• B (3) is wrong - 3 is not a power of 2 and has no direct role here; it's a common trap because it looks like "one per line" thinking, or may be confused with MC/DC which needs N+1 tests.
• C (4) is wrong - 4 would be correct if there were only 2 atomic conditions (2^2 = 4), not 3.

Memory tip: For MCC, think "2 to the power of conditions" - count every individual boolean variable or comparison in the decision, then raise 2 to that count. If you see 3 conditions in a compound if, you immediately know 8 test cases are needed.

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