Based on the state diagram above, how many invalid test cases could be identified in a state table? 2 credits [K3]

Question

Options

• A10
• B12
• C14
• D15

• A
  81% (38)
• B
  4% (2)
• C
  4% (2)
• D
  11% (5)

Explanation

Option A (10) is correct because, in a state table, the total number of entries equals the number of states multiplied by the number of events/inputs. Subtracting the valid (defined) transitions from that total gives the invalid ones - and for the referenced diagram, that calculation yields exactly 10.

Why the distractors are wrong:

• B (12) typically results from miscounting the number of states or events, inflating the total cell count before subtracting valid transitions.
• C (14) often comes from only subtracting a subset of valid transitions, missing some that are implied or self-referencing.
• D (15) is the total number of state-event combinations minus only one valid transition - a sign of forgetting to account for all defined paths in the diagram.

Memory tip: Think of the state table as a grid - States × Events = Total cells. Valid transitions fill some cells; every empty/undefined cell is an invalid test case. Always count the full grid first, then subtract what's defined.

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