Snowflake
COF-R02 · Question #208
Which Snowflake function will interpret an input string as a JSON document, and produce a VARIANT value?
The correct answer is B. json_extract_path_text(). See the full explanation below for the reasoning.
Question
Which Snowflake function will interpret an input string as a JSON document, and produce a VARIANT value?
Options
- Aparse_json()
- Bjson_extract_path_text()
- Cobject_construct()
- Dflatten
How the community answered
(32 responses)- A16% (5)
- B72% (23)
- C3% (1)
- D9% (3)
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