COF-C02 · Question #476
COF-C02 Question #476: Real Exam Question with Answer & Explanation
The correct answer is C: PARSE_JSON. To insert JSON formatted string data into a VARIANT field in Snowflake, the correct function to use is PARSE_JSON. The PARSE_JSON function is specifically designed to interpret a JSON formatted string and convert it into a VARIANT type, which is Snowflake's flexible format for ha
Question
Which function should be used to insert JSON format string data inot a VARIANT field?
Options
- AFLATTEN
- BCHECK_JSON
- CPARSE_JSON
- DTO_VARIANT
Explanation
To insert JSON formatted string data into a VARIANT field in Snowflake, the correct function to use is PARSE_JSON. The PARSE_JSON function is specifically designed to interpret a JSON formatted string and convert it into a VARIANT type, which is Snowflake's flexible format for handling semi-structured data like JSON, XML, and Avro. This function is essential for loading and querying JSON data within Snowflake, allowing users to store and manage JSON data efficiently while preserving its structure for querying purposes. This function's usage and capabilities are detailed in the Snowflake documentation, providing users with guidance on how to handle semi-structured data effectively within their Snowflake environments.
Topics
Community Discussion
No community discussion yet for this question.