CERTIFIED-IN-CYBERSECURITY · Question #180
Which of the following is a valid public IP?
The correct answer is D. 12.123.23.23. IPv4 addresses consist of four octets, each ranging from 0 to 255. Option A (256.231.342.123) is invalid because 256 and 342 exceed the maximum value of 255. Option B (172.213.123.321) is invalid because 321 exceeds 255. Option C (192.168.123.123) uses valid octet values but…
Question
Which of the following is a valid public IP?
Options
- A256.231.342.123
- B172.213.123.321
- C192.168.123.123
- D12.123.23.23
How the community answered
(37 responses)- A5% (2)
- B3% (1)
- C3% (1)
- D89% (33)
Explanation
IPv4 addresses consist of four octets, each ranging from 0 to 255. Option A (256.231.342.123) is invalid because 256 and 342 exceed the maximum value of 255. Option B (172.213.123.321) is invalid because 321 exceeds 255. Option C (192.168.123.123) uses valid octet values but falls within the 192.168.0.0/16 private IP range, making it non-routable on the public internet. Option D (12.123.23.23) has all octets within the valid 0–255 range and does not fall within any reserved private range (10.x.x.x, 172.16–31.x.x, or 192.168.x.x), making it the only valid public IP.
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