IBM
C2180-272 · Question #43
A solution developer is setting up Message Broker for debugging flows. There is a need to set the JVM debug port to 2314 from command line for a specific execution group called "MDM" and a broker…
The correct answer is C. mqsichangeproperties WMBBRK1 -e MDM -o ComIbmJVMManager -n jvmDebugPort -v. See the full explanation below for the reasoning.
Question
A solution developer is setting up Message Broker for debugging flows. There is a need to set the JVM debug port to 2314 from command line for a specific execution group called "MDM" and a broker called "WMBBRK1". Which command does the solution developer need to use?
Options
- Amqsichangebroker WMBBRK1 -e MDM -o ComIbmJVMManager -n jvmDebugPort -v
- Bmqsireportproperties WMBBRK1 -e MDM -i ComIbmJVMManager -n jvmDebugPort -v
- Cmqsichangeproperties WMBBRK1 -e MDM -o ComIbmJVMManager -n jvmDebugPort -v
- Dmqsichangeproperties WMBBRK1 -e MDM -i ComIbmJVMManager -n jvmDebugPort -v
How the community answered
(57 responses)- A14% (8)
- B7% (4)
- C75% (43)
- D4% (2)
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