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A00-280 · Question #34

A00-280 Question #34: Real Exam Question with Answer & Explanation

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Question

Study day is defined as DCMDTE minus RFSTDTC +1 DCMDTE is character data in YYYYMMDD format contains partial date values RFSTDTC is character data in date9 format contains missing values Which statement will compute the study day correctly without producing missing values in the log?

Options

  • ASTUDYDAY=DCMDTE-RFSTDTC+1;
  • BSTUDYDAY=input(DCMDTE,yymmdd8.)-input(RFSTDTC,date9.)+1;
  • Cif RFSTDTC=' ' and length(DCMDTE)=8 then STUDYDAY=input(DCMDTE,yymmdd8.)-input(RFSTDTC,date9.)+1;
  • DIf RFSTDTC=' ' and length(DCMDTE)=8 then STUDYDAY=input(DCMDTE,yymmdd8.)+1; -input(RFSTDTC, yymmdd8.)+1;

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