5V0-35.21 · Question #112
A customer is in the process of creating a Custom Dashboard and has added the following widgets: - Object List - Object Relationship - Alert List The customer's requirements are given below…
The correct answer is C. Connect B to E, and Connect B to G. Option C is correct because the Object List widget's "Selected Object" output point B is the single source that must drive both downstream widgets - connecting B to E feeds the selected object into the Object Relationship widget's input, and connecting B to G feeds it into the…
Question
A customer is in the process of creating a Custom Dashboard and has added the following widgets:
- Object List
- Object Relationship
- Alert List
The customer's requirements are given below:
- Whenever any object is selected in Object List widget, then Object
Relationship widget should show the relationship map of this selected object.
- The Alert List widget should only show this selected object Active
Alerts. Refer to the exhibit:
Which Points in these widgets should be connected to satisfy this requirement?
Exhibit
Options
- AConnect H to G, and Connect E to C.
- BConnect A to D, and Connect G to B.
- CConnect B to E, and Connect B to G.
- DConnect A to D, and Connect A to F.
How the community answered
(35 responses)- A9% (3)
- B11% (4)
- C77% (27)
- D3% (1)
Explanation
Option C is correct because the Object List widget's "Selected Object" output point B is the single source that must drive both downstream widgets - connecting B to E feeds the selected object into the Object Relationship widget's input, and connecting B to G feeds it into the Alert List widget's filter input, satisfying both requirements simultaneously with one source point.
Why the distractors fail:
- A (H→G, E→C) uses points from the wrong widgets or wrong directions - it doesn't originate from the Object List's selection output at all.
- B (A→D, G→B) reverses the data flow by pointing G (Alert List) back into B (Object List), which is backward and would create a nonsensical loop.
- D (A→D, A→F) uses point A, which is likely an input on the Object List rather than its output, so it cannot broadcast a selection to the other widgets.
Memory tip: Think "one broadcaster, two receivers." The Object List broadcasts a selection - find the single output point on that widget (B) and wire it to the input of each widget that needs to receive that selection. If any connection choice has different starting points for the two connections, it's almost certainly wrong.
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