5V0-22.23 · Question #162
An organization wants to configure a new storage policy based on the following requirements: - Failures to tolerate = FTT l/RAID-5 (Erasure Coding) - Number of disk stripes per object = 8 - IOPS…
The correct answer is A. 1. With RAID-5 (Erasure Coding) on a four-node vSAN OSA cluster, the data is divided into three data components and one parity component, each placed on a different host. The number of disk stripes per object = 8 only determines how data is laid out within disks but does not…
Question
An organization wants to configure a new storage policy based on the following requirements:
- Failures to tolerate = FTT l/RAID-5 (Erasure Coding)
- Number of disk stripes per object = 8
- IOPS limit for object = 0
- Object Space Reservation = Thin provisioning
- Flash read cache reservation = 0%
- Disable object checksum = No
- Force provisioning = No
The administrator creates the policy using storage policy-based management and assigns it to a 100GB virtual machine on a four-node vSAN OSA cluster to test the results of the new storage policy. How many components will be created per host for the storage objects of the virtual machine on the vSAN datastore?
Options
- A1
- B2
- C8
- D32
How the community answered
(14 responses)- A64% (9)
- B21% (3)
- C7% (1)
- D7% (1)
Explanation
With RAID-5 (Erasure Coding) on a four-node vSAN OSA cluster, the data is divided into three data components and one parity component, each placed on a different host. The number of disk stripes per object = 8 only determines how data is laid out within disks but does not multiply the number of components per host. Therefore, each host stores one component of the object, resulting in one component per host for the virtual machine's storage object.
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