4A0-102 · Question #74
Click the exhibit. Router R6 is a route reflector with clients R1, R2 and R5. Router R3 advertises the prefix 192.168.1.0/27 to routers R1, R2 and R5. How many routes for prefix 192.168.1.0/27 will…
The correct answer is C. 3. Option C is correct because R3 advertises the prefix 192.168.1.0/27 independently to each of R6's three RR clients (R1, R2, and R5), and each client then forwards that route advertisement up to their route reflector, R6 - resulting in 3 separate route advertisements reaching…
Question
Options
- A1
- B2
- C3
- DNone
How the community answered
(21 responses)- A5% (1)
- B14% (3)
- C76% (16)
- D5% (1)
Explanation
Option C is correct because R3 advertises the prefix 192.168.1.0/27 independently to each of R6's three RR clients (R1, R2, and R5), and each client then forwards that route advertisement up to their route reflector, R6 - resulting in 3 separate route advertisements reaching R6.
Why the distractors are wrong:
- A (1): R6 does not receive a single consolidated route; it receives individual advertisements from each client independently - BGP route reflectors don't merge incoming updates.
- B (2): There is no reason for one client to be excluded; all three clients (R1, R2, R5) receive the prefix from R3 and each advertises it to R6.
- D (None): R6 absolutely receives routes - it's the RR and its clients are peering with it specifically to forward their learned routes.
Memory tip: "Clients = copies." Count how many RR clients learned the prefix - that's exactly how many route advertisements the RR receives. Here, 3 clients learned it → R6 receives 3 routes.
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