350-601 Question #575: Real Exam Question with Answer & Explanation

The correct answer is A: interface_name = json_object["if-name"]. To retrieve the network interface name 'eth0' from the Python dictionary json_object, access the dictionary using its corresponding key, which is 'if-name'.

Automation

Question

Refer to the exhibit. A network engineer must retrieve the network interface name from a JSON object. The engineer loads the JSON into a Python dictionary named json_object. Which code snippet completes the Python script?

Options

Ainterface_name = json_object["if-name"]
Binterface_name = json_object[0]
Cinterface_name = json_object["eth0"]
Dinterface_name = json_object[0][2]

Explanation

To retrieve the network interface name 'eth0' from the Python dictionary json_object, access the dictionary using its corresponding key, which is 'if-name'.

Common mistakes.

B. json_object[0] attempts to access the dictionary using a numeric index, which is not valid for Python dictionaries as they are not ordered sequences.
C. json_object["eth0"] attempts to use the value "eth0" as a key, which would result in a KeyError because "eth0" is not a key in the dictionary.
D. json_object[0][2] attempts to access a dictionary by a numeric index and then further index an element, which is entirely incorrect for this simple key-value JSON structure.

Concept tested. Python dictionary access for JSON data

Reference. https://docs.python.org/3/library/json.html

Topics

#Python#JSON Parsing#Dictionary Access#Network Automation

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