312-92 · Question #42
What type of encryption will be used from the following code? Dim Publickey As Byte() = {214,46,220,83,160,73,40,39,201 155,19,202,3,11,191,178,56,74,90,36,248,103…
The correct answer is D. Asymmetric encryption. See the full explanation below for the reasoning.
Question
What type of encryption will be used from the following code? Dim Publickey As Byte() = {214,46,220,83,160,73,40,39,201 155,19,202,3,11,191,178,56,74,90,36,248,103, 18,144,170,163,145,87,54,61,34,220,222,207, 137,149,173,14,92,120,206,222,158,28,40,24, 30,16,175,108,128,35,203,118,40,121,113,125, 216,130,11,24,9,0,48,194,240,105,44,76,34,57, 249,228,125,80,38,9,136,29,117,207,139,168,181, 85,137,126,10,126,242,120,247,121,8,100,12,201, 171,38,226,193,180,190,117,177,87,143,242,213, 11,44,18,0,113,93,106,99,179,68,175,211,164,116 64,148,226,254,172,147} Dim Exponent As Byte() = {1,0,1} Dim Encrypted SymmetricKey() As Byte Dim Encrypted SymmetricIV() As Byte Dim RSA as New RSACryptoServiceProvider() Dim RSAKeyInfo As New RSAParameters() RSAKeyInfo.Modules = PublicKey RSAKeyInfo.Exponent = Exponent RSA.ImportParameters(RSAKeyInfo) Dim RM As New RijendaelManaged() EncryptedSymmetricKey = RSA.Encrypt(RM.Key,False) EncryptedSymmetricIV = RSA.Encrypt(RM.Key,False)
Options
- ASymmetric encryption
- BMITM encryption
- CReverse-key encryption
- DAsymmetric encryption
How the community answered
(27 responses)- A15% (4)
- B7% (2)
- C4% (1)
- D74% (20)
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