312-50V9 · Question #353
The chance of a hard drive failure is known to be once every four years. The cost of a new hard drive is $500. EF (Exposure Factor) is about 0.5. Calculate for the Annualized Loss Expectancy (ALE).
The correct answer is A. $62.5. The correct answer is A. $62.50. ALE (Annualized Loss Expectancy) is calculated as: ALE = SLE × ARO. First, calculate SLE (Single Loss Expectancy): SLE = Asset Value × EF = $500 × 0.5 = $250. Next, calculate ARO (Annual Rate of Occurrence): the drive fails once every 4 years…
Question
The chance of a hard drive failure is known to be once every four years. The cost of a new hard drive is $500. EF (Exposure Factor) is about 0.5. Calculate for the Annualized Loss Expectancy (ALE).
Options
- A$62.5
- B$250
- C$125
- D$65.2
How the community answered
(51 responses)- A80% (41)
- B12% (6)
- C6% (3)
- D2% (1)
Explanation
The correct answer is A. $62.50. ALE (Annualized Loss Expectancy) is calculated as: ALE = SLE × ARO. First, calculate SLE (Single Loss Expectancy): SLE = Asset Value × EF = $500 × 0.5 = $250. Next, calculate ARO (Annual Rate of Occurrence): the drive fails once every 4 years, so ARO = 1/4 = 0.25. Finally: ALE = $250 × 0.25 = $62.50. This formula is a core part of quantitative risk analysis in security certifications (CEH, CISSP, Security+).
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