A sophisticated attacker targets your web server with the intent to execute a Denial of Service (DoS) attack. His strategy involves a unique mixture of TCP SYN, UDP, and ICMP floods, using 'r'…

Question

Options

• Ah=1999 (prime): Despite the attacker's packet flood, the server can handle these requests,
• Bh=2003 (prime): The server can manage more packets than the attacker is sending, hence it
• Ch=1993 (prime): Despite being less than 'r', the server's prime number capacity keeps it barely
• Dh=1987 (prime): The attacker's packet rate exceeds the server's capacity, causing potential

• A
  6% (2)
• B
  6% (2)
• C
  3% (1)
• D
  85% (29)

Explanation

Explanation

Option D is correct because h=1987 is less than r=2010, meaning the attacker's packet rate exceeds the server's handling capacity (r > h), which directly satisfies the condition for the server to become overwhelmed and unresponsive. Options A (h=1999) and B (h=2003) are incorrect because both values are greater than r=2010... wait - h=1999 < 2010, so let me clarify: Option B (h=2003) is incorrect because 2003 > 2010 is false - 2003 < 2010, but the question states the server can manage more, which is factually wrong. Actually, the key distinction is that Option D (h=1987) is the smallest prime listed, making it the furthest below r=2010 and therefore the scenario where the server is most clearly overwhelmed. Options A (h=1999) and C (h=1993) also fall below r=2010, but their answer descriptions misleadingly claim the server survives - only Option D's description accurately states the server falters due to the packet rate exceeding capacity.

Memory Tip: Remember the simple rule - if r > h, the server fails. Think of it as "Rate beats Handling = Havoc." Always compare the two numbers directly; the prime/composite detail is a red herring to test whether you stay focused on the core inequality.

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