nerdexam
EC-Council

312-50V11 · Question #344

What is the broadcast address for the subnet 190.86.168.0/22?

The correct answer is C. 190.86.171.255. For the subnet 190.86.168.0/22, the broadcast address is 190.86.171.255, found by setting all 10 host bits to 1.

Scanning Networks

Question

What is the broadcast address for the subnet 190.86.168.0/22?

Options

  • A190.86.168.255
  • B190.86.255.255
  • C190.86.171.255
  • D190.86.169.255

How the community answered

(19 responses)
  • A
    16% (3)
  • B
    5% (1)
  • C
    74% (14)
  • D
    5% (1)

Why each option

For the subnet 190.86.168.0/22, the broadcast address is 190.86.171.255, found by setting all 10 host bits to 1.

A190.86.168.255

190.86.168.255 is the broadcast address of the narrower /24 subnet 190.86.168.0/24; the /22 block spans four contiguous /24 networks and therefore has a higher broadcast address.

B190.86.255.255

190.86.255.255 would be the broadcast address for a /16 block (190.86.0.0/16), which is a far larger address space than the /22 specified in the question.

C190.86.171.255Correct

A /22 prefix means 22 bits are used for the network, leaving 10 host bits (32 - 22 = 10): the lowest 2 bits of the third octet and all 8 bits of the fourth octet. Setting all host bits to 1 changes the third octet from 168 (10101000 in binary) to 171 (10101011 in binary) and the fourth octet to 255, giving a broadcast of 190.86.171.255 and a usable host range of 190.86.168.1 to 190.86.171.254.

D190.86.169.255

190.86.169.255 is the broadcast address of the second /24 block (190.86.169.0/24) contained within the /22, not of the /22 supernet itself.

Concept tested: IPv4 /22 subnetting broadcast address calculation

Source: https://docs.cisco.com/c/en/us/support/docs/ip/routing-information-protocol-rip/13788-3.html

Topics

#subnetting#broadcast address#CIDR#IP addressing

Community Discussion

No community discussion yet for this question.

Full 312-50V11 Practice