312-50V11 · Question #344
What is the broadcast address for the subnet 190.86.168.0/22?
The correct answer is C. 190.86.171.255. For the subnet 190.86.168.0/22, the broadcast address is 190.86.171.255, found by setting all 10 host bits to 1.
Question
What is the broadcast address for the subnet 190.86.168.0/22?
Options
- A190.86.168.255
- B190.86.255.255
- C190.86.171.255
- D190.86.169.255
How the community answered
(19 responses)- A16% (3)
- B5% (1)
- C74% (14)
- D5% (1)
Why each option
For the subnet 190.86.168.0/22, the broadcast address is 190.86.171.255, found by setting all 10 host bits to 1.
190.86.168.255 is the broadcast address of the narrower /24 subnet 190.86.168.0/24; the /22 block spans four contiguous /24 networks and therefore has a higher broadcast address.
190.86.255.255 would be the broadcast address for a /16 block (190.86.0.0/16), which is a far larger address space than the /22 specified in the question.
A /22 prefix means 22 bits are used for the network, leaving 10 host bits (32 - 22 = 10): the lowest 2 bits of the third octet and all 8 bits of the fourth octet. Setting all host bits to 1 changes the third octet from 168 (10101000 in binary) to 171 (10101011 in binary) and the fourth octet to 255, giving a broadcast of 190.86.171.255 and a usable host range of 190.86.168.1 to 190.86.171.254.
190.86.169.255 is the broadcast address of the second /24 block (190.86.169.0/24) contained within the /22, not of the /22 supernet itself.
Concept tested: IPv4 /22 subnetting broadcast address calculation
Source: https://docs.cisco.com/c/en/us/support/docs/ip/routing-information-protocol-rip/13788-3.html
Topics
Community Discussion
No community discussion yet for this question.