Refer to the exhibit. Which output is expected when this code runs? def test(definedArgument, args, *kwargs): print (definedArgument) print (args) print (kwargs["test1"]) test("USER",1,2,True,"Hello W

Question

Options

• AUSER definedArgument Args kwargs
• BUSER 1 Test Passed!
• CUSER (1, 2, True, 'Hello World') test1
• DUSER (1, 2, True, 'Hello World') Test Passed!

• A
  9% (3)
• B
  3% (1)
• C
  17% (6)
• D
  71% (25)

Explanation

Option D is correct because Python assigns "USER" to definedArgument, collects the remaining positional arguments (1, 2, True, 'Hello World') into a tuple called args, and stores keyword arguments in the kwargs dictionary - so kwargs["test1"] retrieves the value "Test Passed!", not the key name.

Why the distractors fail:

• A is wrong because Python prints the values of variables, not their names - you'd never see "definedArgument" or "Args" printed.
• B is wrong because *args captures all extra positional arguments as a single tuple, not just the first one (1).
• C is wrong because kwargs["test1"] uses "test1" as a key to look up its value; it prints "Test Passed!", not the string "test1".

Memory tip: Think of *args as a bag of positional extras (always a tuple) and **kwargs as a labeled bag (always a dict). Accessing kwargs["key"] gives you the value, just like any dictionary lookup.

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