Which password meets ESXi 6.x host password requirements?

The correct answer is A. 8kMVnn2x! ESXi 6.x uses pam_passwdqc for password complexity enforcement. The default policy requires a minimum length of 7 characters and characters drawn from at least 3 of the 4 character classes: uppercase letters, lowercase letters, digits, and special/non-alphanumeric characters…

Section 1 – Configure and Administer vSphere 6.x Security

Question

Options

A8kMVnn2x!
BzNgtnJBA2
CNvgt34kn44
D!b74wr

How the community answered

(43 responses)

A
95% (41)
B
2% (1)
C
2% (1)

Explanation

ESXi 6.x uses pam_passwdqc for password complexity enforcement. The default policy requires a minimum length of 7 characters and characters drawn from at least 3 of the 4 character classes: uppercase letters, lowercase letters, digits, and special/non-alphanumeric characters. Analyzing each option: (A) 8kMVnn2x! - 9 characters, contains digits (8,2), lowercase (k,n,n,x), uppercase (M,V), and a special character (!); uses all 4 classes - VALID. (B) zNgtnJBA2 - 9 characters but contains only 3 classes (lower, upper, digits) with no special character - does not meet the special character requirement. (C) Nvgt34kn44 - 10 characters but again only 3 classes (upper, lower, digits) with no special character - fails the same way. (D) !b74wr - only 6 characters, which is below the 7-character minimum - too short. Only option A satisfies all requirements including the special character.

Topics

#password policy#ESXi authentication#password complexity#ESXi security

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