Zend
200-550 · Question #162
Which is the most efficient way to determine if a key is present in an array, assuming the array has no NULL values?
The correct answer is B. isset($a['key']). See the full explanation below for the reasoning.
Question
Which is the most efficient way to determine if a key is present in an array, assuming the array has no NULL values?
Options
- Ain_array('key', array_keys($a))
- Bisset($a['key'])
- Carray_key_exists('key', $a)
- DNone of the above
How the community answered
(32 responses)- A16% (5)
- B75% (24)
- C6% (2)
- D3% (1)
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