Zend
200-550 · Question #129
Which is the most efficient way to determine if a key is present in an array, assuming the array has no NULL values?
The correct answer is C. array_key_exists('key', $a). See the full explanation below for the reasoning.
Question
Which is the most efficient way to determine if a key is present in an array, assuming the array has no NULL values?
Options
- Ain_array('key', array_keys($a))
- Bisset($a['key'])
- Carray_key_exists('key', $a)
- DNone of the above
How the community answered
(20 responses)- A5% (1)
- B10% (2)
- C85% (17)
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