Zend
200-530 · Question #68
Which is the most efficient way to determine if a key is present in an array, assuming the array has no NULL values?
The correct answer is C. array_key_exists('key', $a). See the full explanation below for the reasoning.
Question
Which is the most efficient way to determine if a key is present in an array, assuming the array has no NULL values?
Options
- Ain_array('key', array_keys($a))
- Bisset($a['key'])
- Carray_key_exists('key', $a)
- DNone of the above
How the community answered
(23 responses)- A9% (2)
- B13% (3)
- C74% (17)
- D4% (1)
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