You want to run the following PHP 4 code with PHP 5. In the following example, which access modifier in PHP 5 is equivalent to "var"? class Test { var $tester; }

The correct answer is C. public. See the full explanation below for the reasoning.

Question

You want to run the following PHP 4 code with PHP 5. In the following example, which access modifier in PHP 5 is equivalent to "var"? class Test { var $tester; }

Options

Aprotected
Binvisible
Cpublic
Dprivate
Eoutofscope

How the community answered

(15 responses)

A
7% (1)
B
13% (2)
C
80% (12)

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