Drag and Drop Question Refer to the exhibit. Drag and drop the prefix lengths from the left onto the corresponding prefixes on the right. Not all prefixes are used. Answer:

The correct answer is 255.255.255.128; 255.255.255.224; 255.255.255.240; 255.255.255.248; 255.255.255.252. Each subnet mask corresponds to a specific prefix length based on the number of consecutive 1-bits in binary: 255.255.255.128 = /25 (1 host bit), 255.255.255.224 = /27 (3 host bits), 255.255.255.240 = /28 (4 host bits), 255.255.255.248 = /29 (5 host bits), and 255.255.255.252 = /

Submitted by tom_us· Mar 5, 2026Network Fundamentals – Understand IP addressing and subnetting, including the relationship between dotted-decimal subnet masks and CIDR prefix lengths (CCNA 200-301 Domain 1)

Question

Drag and Drop Question Refer to the exhibit. Drag and drop the prefix lengths from the left onto the corresponding prefixes on the right. Not all prefixes are used. Answer:

Exhibits

Answer Area

Drag items

255.255.255.128255.255.255.224255.255.255.240255.255.255.248255.255.255.252

Correct arrangement

255.255.255.128
255.255.255.224
255.255.255.240
255.255.255.248
255.255.255.252

Explanation

Each subnet mask corresponds to a specific prefix length based on the number of consecutive 1-bits in binary: 255.255.255.128 = /25 (1 host bit), 255.255.255.224 = /27 (3 host bits), 255.255.255.240 = /28 (4 host bits), 255.255.255.248 = /29 (5 host bits), and 255.255.255.252 = /30 (6 host bits). Converting the last octet to binary confirms each mapping: 128=10000000, 224=11100000, 240=11110000, 248=11111000, 252=11111100. All five options are used in this question as each mask has a unique and direct prefix-length equivalent.

Topics

#Subnet Masks#CIDR Notation#IPv4 Addressing#Binary Conversion

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