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200-301 · Question #820
200-301 Question #820: Real Exam Question with Answer & Explanation
The correct answer is A: 192.168.4.67. To identify valid host addresses within a 192.168.4.0 network subnetted with a /26 mask, one must determine the network and broadcast addresses for each subnet.
Submitted by fernanda_arg· Mar 5, 2026[DOMAIN_LIST_MISSING_IN_PROMPT]
Question
An administrator is working with the 192.168.4.0 netwrok, which has been subnetted with a /26 mask. Which two addresses can be assigned to hosts within the same subnet? (Choose two.)
Options
- A192.168.4.67
- B192.168.4.61
- C192.168.4.128
- D192.168.4.132
- E192.168.4.125
- F192.168.4.63
Explanation
To identify valid host addresses within a 192.168.4.0 network subnetted with a /26 mask, one must determine the network and broadcast addresses for each subnet.
Common mistakes.
- B. 192.168.4.61 is a valid host address but belongs to the first subnet (192.168.4.0/26), not the same subnet as options A and E.
- C. 192.168.4.128 is the network address for the third subnet (192.168.4.128/26) and cannot be assigned to a host.
- D. 192.168.4.132 is a valid host address but belongs to the third subnet (192.168.4.128/26), not the same subnet as options A and E.
- F. 192.168.4.63 is the broadcast address for the first subnet (192.168.4.0/26) and cannot be assigned to a host.
Concept tested. IPv4 Subnetting and Host Address Assignment
Topics
#Subnetting#IP Addressing#CIDR notation#Host addresses
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