200-201 · Question #438
What does this regular expression do? \b(192|172).(168|1[6-9]|2[0-9]|3[0-1]).[0-9]{1,3}.[0-9]{1.3}\b
The correct answer is A. It searches for private IP addresses except 10.0.0.0/8 IP address range. This regular expression is designed to match IP addresses from the private IP ranges of 192.168.0.0/16 and 172.16.0.0/12 (but excludes 10.0.0.0/8). Here's how it works: - b: Matches a word boundary, ensuring the IP is isolated. - (192|172): Matches either 192 or 172 as the…
Question
What does this regular expression do? \b(192|172).(168|1[6-9]|2[0-9]|3[0-1]).[0-9]{1,3}.[0-9]{1.3}\b
Options
- AIt searches for private IP addresses except 10.0.0.0/8 IP address range.
- BIt matches any IP addresses within 172.16.0.0/16 IP address range.
- CIt extracts lines with 192.168.0.0/16 IP address range from the text.
- DIt searches for lines with private IP addresses in text.
How the community answered
(13 responses)- A69% (9)
- C8% (1)
- D23% (3)
Explanation
This regular expression is designed to match IP addresses from the private IP ranges of 192.168.0.0/16 and 172.16.0.0/12 (but excludes 10.0.0.0/8). Here's how it works: - b: Matches a word boundary, ensuring the IP is isolated. - (192|172): Matches either 192 or 172 as the first octet. - (168|1[6-9]|2[0-9]|3[0-1]): Matches the second octet. For 192, it matches 168. For 172, it - [0-9]{1,3}: Matches the third and fourth octets (any number from 0 to 255). - b: Ensures the IP address ends as an isolated entity. The pattern specifically targets private IP ranges 192.168.0.0/16 and 172.16.0.0/12, excluding the 10.0.0.0/8 range.
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