Oracle
1Z0-851 · Question #156
Given: 11. public class Rainbow { 12. public enum MyColor { 13. RED(0xff0000), GREEN(0x00ff00), BLUE(0x0000ff); 14. private final int rgb; 15. MyColor(int rgb) { this.rgb = rgb; } 16. public int…
The correct answer is B. MyColor treeColor = MyColor.GREEN. See the full explanation below for the reasoning.
Question
Given: 11. public class Rainbow { 12. public enum MyColor { 13. RED(0xff0000), GREEN(0x00ff00), BLUE(0x0000ff); 14. private final int rgb; 15. MyColor(int rgb) { this.rgb = rgb; } 16. public int getRGB() { return rgb; } 17. }; 18. public static void main(String[] args) { 19. // insert code here 20. } 21. } Which code fragment, inserted at line 19, allows the Rainbow class to compile?
Options
- AMyColor skyColor = BLUE;
- BMyColor treeColor = MyColor.GREEN;
- Cif(RED.getRGB() < BLUE.getRGB()) { }
- DCompilation fails due to other error(s) in the code.
- EMyColor purple = new MyColor(0xff00ff);
- FMyColor purple = MyColor.BLUE + MyColor.RED;
How the community answered
(41 responses)- A2% (1)
- B76% (31)
- C7% (3)
- E2% (1)
- F12% (5)
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