Given: 23. Object [] myObjects = { 24. new Integer(12), 25. new String("foo"), 26. new Integer(5), 27. new Boolean(true) 28. }; 29. Arrays.sort(myObjects); 30. for(int i=0; i<myObjects.length; i++)…

The correct answer is C. A ClassCastException occurs in line 29. Exception in thread "main" java.lang.ClassCastException: java.lang.String cannot be cast to java.lang.Integer at java.lang.Integer.compareTo(Unknown Source) at java.util.Arrays.mergeSort(Unknown Source) at java.util.Arrays.sort(Unknown Source) at Barn.main(Barn.java:29)

Analyzing and Troubleshooting System Problems

Question

Given: 23. Object [] myObjects = { 24. new Integer(12), 25. new String("foo"), 26. new Integer(5), 27. new Boolean(true) 28. }; 29. Arrays.sort(myObjects); 30. for(int i=0; i<myObjects.length; i++) { 31. System.out.print(myObjects[i].toString()); 32. System.out.print(" "); 33. } What is the result?

Options

ACompilation fails due to an error in line 23.
BCompilation fails due to an error in line 29.
CA ClassCastException occurs in line 29.
DA ClassCastException occurs in line 31.
EThe value of all four objects prints in natural order.

How the community answered

(26 responses)

A
4% (1)
B
15% (4)
C
73% (19)
D
8% (2)

Explanation

Exception in thread "main" java.lang.ClassCastException: java.lang.String cannot be cast to java.lang.Integer at java.lang.Integer.compareTo(Unknown Source) at java.util.Arrays.mergeSort(Unknown Source) at java.util.Arrays.sort(Unknown Source) at Barn.main(Barn.java:29)

Topics

#Java Arrays.sort#ClassCastException#Comparable interface#mixed-type array

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