Consider the following ZFS configuration: You have created snapshots of the home directories which are as follows: You have another storage pool named bpool on the same system. You use the following…

Question

Options

• Abpool/export/home/ bpool/export/home/curly
• Bbpool/export/home/ bpool/export/home/curly bpool/export/[email protected]
• Cbpool/export/home/ bpool/export/home/curly [email protected]
• Dbpool/curly bpool/[email protected]
• Ebpool/curly
• Fbpool/curly

• A
  2% (1)
• C
  12% (6)
• D
  76% (38)
• E
  6% (3)
• F
  4% (2)

Explanation

Option D is correct because zfs recv without the -d flag uses only the last path component of the source dataset as the name under the destination pool. The source dataset is rpool/export/home/curly (the leaf dataset for user curly), so its last component - curly - is appended to bpool, yielding bpool/curly. The receive operation also creates the accompanying snapshot bpool/[email protected], which corresponds to the snapshot embedded in the send stream for that dataset.

Why the other options are wrong:

• A, B, C are wrong because they preserve the intermediate path components export/home, which would only happen if zfs recv -d were used - the -d flag instructs ZFS to replicate the full source path (minus the pool name) under the destination.
• E and F are wrong (and identical) because they omit the snapshot bpool/[email protected]; a zfs recv of a snapshot stream always creates both the dataset and its snapshot.

Memory tip: Think of -d as "directory structure preserved" - with -d, ZFS recreates the full path; without -d, only the last component is used. When in doubt, ask: "did the command use -d?" If not, strip everything but the leaf.

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