Given this code fragment: int x = 0; do { x++; if (x == 1) { continue; } System.out.println(x); } while (x < 1); What is the result?

The correct answer is D. The program prints nothing. D is correct because the loop body executes exactly once: x increments from 0 to 1, the if (x == 1) condition is true so continue fires - skipping System.out.println(x) - and then the while (x < 1) condition evaluates to false (since 1 < 1 is false), ending the loop with no…

Controlling Program Flow

Question

Given this code fragment:
int x = 0;
do {
x++;
if (x == 1) {
continue;
}
System.out.println(x);
} while (x < 1);
What is the result?

Options

A01
B0
C1
DThe program prints nothing.
EIt prints 1 in the infinite loop.

How the community answered

(37 responses)

A
11% (4)
B
3% (1)
C
5% (2)
D
78% (29)
E
3% (1)

Explanation

D is correct because the loop body executes exactly once: x increments from 0 to 1, the if (x == 1) condition is true so continue fires - skipping System.out.println(x) - and then the while (x < 1) condition evaluates to false (since 1 < 1 is false), ending the loop with no output ever produced.

Why the distractors fail: C ("1") is the most tempting trap - x does equal 1, but continue skips past the print statement before it can execute. A ("01") and B ("0") are impossible because x++ runs first in every iteration, meaning x is never 0 when println could fire. E (infinite loop) misreads the loop direction - once x reaches 1, the while condition x < 1 immediately becomes false and exits.

Memory tip: In a do-while, continue doesn't restart the body - it jumps directly to the condition check. Always ask yourself: "What is x's value when the condition is evaluated?" Here, continue lands you at while (x < 1) with x = 1, which kills the loop before a second iteration can ever print anything.

Topics

#do-while loop#continue statement#loop control flow#loop conditions

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