public class Test { private String strings; } Which two construct ors will compile and set the class field strings? (Choose two.)

Question

Options

• Apublic Test(List<String> strings) { this.strings = strings; }
• Bpublic Test(String... strings) { this.strings = strings; }
• Cpublic Test(String... strings) { this.strings = strings; }
• Dpublic Test(String strings) { this.strings = strings; }
• Epublic Test(String[] strings) { this.strings = strings; }

• A
  4% (2)
• B
  6% (3)
• C
  79% (37)
• D
  11% (5)

Explanation

Options C and E are correct because the field strings is of type String[] (the brackets appear lost in formatting), and both constructors assign a compatible String[] value to it. In option C, the varargs parameter String... strings is syntactic sugar for String[] - the compiler treats them identically at the bytecode level, so the assignment this.strings = strings is valid. In option E, String[] strings explicitly declares an array parameter, which directly matches the field type.

Why the others are wrong:

• A passes a List<String>, which is not assignment-compatible with String[] - you'd need toArray() to convert it.
• B appears identical to C as printed, suggesting a typo in the question; treat it as a distractor (perhaps the original had a different body or missing assignment).
• D passes a single String scalar, which cannot be assigned to a String[] field without wrapping (e.g., new String[]{strings}).

Memory tip: Varargs (T...) and array (T[]) are interchangeable as parameter types for assignment purposes - both are T[] under the hood. When you see a String[] field, any constructor that supplies a String[] (explicitly or via varargs) will compile cleanly.

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