1Z0-819 · Question #160
Which of these initialization statements are correct? (Choose three.)
The correct answer is A. int x = 12_34; B. short sh = (short) 'A'; F. int[][] x = {{1,1},{2,2}}. Options A, B, and F are valid Java initialization statements: A (int x = 12_34) correctly uses the underscore-in-numeric-literals feature from Java 7, where underscores between digits are legal and the value simply equals 1234; B (short sh = (short) 'A') performs a valid…
Question
Options
- Aint x = 12_34;
- Bshort sh = (short) 'A';
- CString name = new String("1+2")+(999 (232)");
- DBoolean true = (4 == 4);
- Efloat f = 1.6f;
- Fint[][] x = {{1,1},{2,2}};
- Gbyte b = 10;char c = b;
How the community answered
(46 responses)- A85% (39)
- C4% (2)
- D2% (1)
- E9% (4)
Explanation
Options A, B, and F are valid Java initialization statements: A (int x = 12_34) correctly uses the underscore-in-numeric-literals feature from Java 7, where underscores between digits are legal and the value simply equals 1234; B (short sh = (short) 'A') performs a valid explicit narrowing cast from char (Unicode value 65) to short, which fits within the short range; and F (int[][] x = {{1,1},{2,2}}) uses correct 2D array initializer shorthand syntax.
The distractors fail for distinct reasons: C has a syntax error with malformed string/parenthesis structure; D uses true as a variable name, which is illegal because true is a reserved literal in Java; G tries to implicitly assign a byte to a char without a cast - illegal because byte is signed and char is unsigned, requiring char c = (char) b;; and E (float f = 1.6f) is worth flagging - it is actually syntactically valid Java, so if your exam marks it wrong, that may be an exam error.
Memory tip: When scanning initialization questions, hunt for three traps in order: reserved words used as identifiers (true, false, null), implicit narrowing conversions missing a cast (especially byte→char), and broken literal syntax - these cover the majority of trick answers.
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