Given the code fragment: public static void main(String[] args) { int iterations = 100; while (count < iterations) { System.out.println("Iteration " + count); count++; } } What is the result?

The correct answer is D. An error occurs during compilation. Option D is correct because the variable count is never declared anywhere in the code - only iterations is declared. Java's compiler performs strict type checking and will refuse to compile any code that references an undeclared variable, throwing a cannot find symbol error…

Java Basics

Question

Given the code fragment:
public static void main(String[] args) {
int iterations = 100;
while (count < iterations) {
System.out.println("Iteration " + count);
count++;
}
}
What is the result?

Options

AThe program compiles and nothing is printed.
BIteration plus an increasing number is printed 100 times.
CIteration plus an increasing number is printed 99 times.
DAn error occurs during compilation.

How the community answered

(51 responses)

A
6% (3)
B
4% (2)
C
2% (1)
D
88% (45)

Explanation

Option D is correct because the variable count is never declared anywhere in the code - only iterations is declared. Java's compiler performs strict type checking and will refuse to compile any code that references an undeclared variable, throwing a cannot find symbol error before the program ever runs.

Options A, B, and C are all wrong for the same fundamental reason: they describe runtime behavior, but the program never reaches runtime. A compilation error halts everything before execution begins, so questions about what gets printed are moot.

Memory tip: In Java, declaration before use is a compile-time rule, not a runtime one. Whenever you see a variable used without a matching declaration in scope, think "compiler catches it" - the answer will always point to a compilation error, not a runtime result.

Topics

#variable declaration#compilation errors#variable scope#control flow

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