Given: public class Course { public static void main (String [] args) { double courseFee = 1000.0; float percentage = 5.0f; // line n1 newFee = courseFee * percentage; System.out.println (newFee); }…

Question

Options

• Aint newFee;
• Bdouble newFee;
• Clong newFee;
• Dfloat newFee;

• B
  93% (37)
• C
  3% (1)
• D
  5% (2)

Explanation

Option B is correct because multiplying a double by a float in Java produces a double result - the float is automatically promoted to double during the operation, and only a double variable can hold that result without an explicit cast.

Why the distractors fail:

• A (int) and C (long) are integer types; assigning a floating-point result to them requires an explicit cast, so the compiler rejects the implicit narrowing conversion.
• D (float) is a narrower floating-point type than double; Java won't silently shrink a double into a float, so this also causes a compile error.

Memory tip: Think of Java's numeric promotion as a "widening ladder" - int → long → float → double. Any arithmetic involving a double climbs to the top, and the result must be stored in a type at that level or higher. If the receiver type sits below the result type on the ladder, you need an explicit cast or the code won't compile.

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