Given: public class MyFor1 { public static void main(String[] args) { int[] x = {6, 7, 8}; for (int i : x) { System.out.print(i + " "); i++; } } } What is the result?

Question

Options

• A6 7 8
• B7 8 9
• C0 1 2
• D6 8 10
• ECompilation fails

• A
  77% (50)
• B
  3% (2)
• C
  12% (8)
• D
  6% (4)
• E
  2% (1)

Explanation

Option A is correct because Java's enhanced for-each loop assigns each array element to i as a local copy - System.out.print(i + " ") runs first, printing the original values 6 7 8, and then i++ increments only that local copy, which is immediately discarded before the next iteration.

Why the distractors fail:

• B (7 8 9): Would require i++ to execute before the print, but it comes after - and even then, only modifies a copy.
• C (0 1 2): Confuses the loop variable with the array index; in a for-each loop, i holds the value, not the position.
• D (6 8 10): Would require i++ to carry over into the next iteration, but the loop variable is re-assigned from the array on each pass.
• E (Compilation fails): The syntax is perfectly valid Java - i++ on an int inside a loop is legal, just ineffective here.

Memory tip: Think of a for-each loop variable as a "read-only snapshot" - you can read the array's value through it, but writing to it is like writing on a sticky note you immediately throw away. If you need to modify the original array, use a traditional index-based for loop.

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