Given: public class X { public static void main(String[] args) { String theString = "Hello World"; System.out.println(theString.charAt(11)); } } What is the result?

Question

Options

• AThe program prints nothing
• Bd
• CA StringIndexOutOfBoundsException is thrown at runtime.
• DAnArrayIndexOutOfBoundsException is thrown at runtime.
• EA NullPointerException is thrown at runtime.

• A
  9% (3)
• B
  3% (1)
• C
  82% (27)
• E
  6% (2)

Explanation

charAt(11) throws a StringIndexOutOfBoundsException because "Hello World" has exactly 11 characters (indices 0–10), making index 11 one past the last valid position - Java's String class explicitly throws this exception when an index is out of range. Option A is wrong because the program does not reach println silently; it crashes. Option B is wrong because 'd' (index 10, the last character) would require charAt(10), not charAt(11). Option D is wrong because String is not an array - ArrayIndexOutOfBoundsException applies to array access (arr[i]), not String methods. Option E is wrong because theString is clearly initialized and not null, so no NPE can occur. Memory tip: Count the characters in the string first - "Hello World" is 11 chars, so valid indices are 0 to 10; any index ≥ length triggers StringIndexOutOfBoundsException, which is always the culprit for charAt/substring range errors on String.

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