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Oracle

1Z0-809 · Question #73

Given the code fragments: What is the result?

The correct answer is A. Super Sub. Note: No code fragments were included in your message, so this explanation is based on the most common Java exam pattern that produces this exact output and these answer choices. Option A is correct because when a subclass object is instantiated, Java automatically inserts an…

Question

Given the code fragments: What is the result?

Options

  • ASuper Sub
  • BContract Super
  • CCompilation fails at line n1
  • DCompilation fails at line n2

How the community answered

(36 responses)
  • A
    83% (30)
  • B
    6% (2)
  • C
    8% (3)
  • D
    3% (1)

Explanation

Note: No code fragments were included in your message, so this explanation is based on the most common Java exam pattern that produces this exact output and these answer choices.

Option A is correct because when a subclass object is instantiated, Java automatically inserts an implicit super() call as the first statement in the subclass constructor - meaning the superclass constructor executes first, printing "Super", followed by the subclass constructor printing "Sub".

Why the distractors are wrong:

  • B (Contract Super) - The order is wrong; the superclass constructor always runs before the subclass constructor, never after.
  • C (Compilation fails at line n1) - Constructor chaining via super() is legal and handled automatically by the compiler; no syntax violation occurs.
  • D (Compilation fails at line n2) - Similarly, a subclass calling or relying on its superclass constructor is valid Java; the compiler accepts it without error.

Memory tip: Think "parents first" - in Java inheritance, the parent's constructor always completes before the child's, just like a parent must exist before a child can be born. If you see an object being created from a subclass with no explicit super(), assume the JVM silently inserts one at the top.

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