Given the code fragments: class Caller implements Callable { String str; public Caller (String s) {this.str=s;} public String call() throws Exception { return str.concat ("Caller");} } class Runner implements Runnable { String str; public Runner (String s) {this.str=s;} public void run () { System.out.println (str.concat ("Runner"));} } and public static void main (String[] args) throws InterruptedException, ExecutionException { Executorservice es = Executors.newFixedThreadPool(2); Future f1 = es.submit (new Caller ("Call")); Future f2 = es.submit (new Runner ("Run")); String str1 = (String) f1.get(); //line n1 String str2 = (String) f2.get(); System.out.println(str1 +""+ str2); } What is the result?

Question

Given the code fragments:

class Caller implements Callable<String> {
 String str;
 public Caller (String s) {this.str=s;}
 public String call() throws Exception { return str.concat
("Caller");}
}
class Runner implements Runnable {
 String str;
 public Runner (String s) {this.str=s;}
 public void run () { System.out.println (str.concat ("Runner"));}
}

and

public static void main (String[] args) throws InterruptedException,
ExecutionException
{
 Executorservice es = Executors.newFixedThreadPool(2);
 Future f1 = es.submit (new Caller ("Call"));
 Future f2 = es.submit (new Runner ("Run"));
 String str1 = (String) f1.get(); //line n1
 String str2 = (String) f2.get();
 System.out.println(str1 +""+ str2);
}

What is the result?

Accepted Answer

B. The program terminates after printing: Run Runner Call Caller : Run

Answer

A. The program prints: Run Runner Call Caller : null And the program does not terminate.

Answer

C. A compilation error occurs at line n1.

Answer

D. An Execution is thrown at run time.

Given the code fragments: class Caller implements Callable<String> { String str; public Caller (String s) {this.str=s;} public String call() throws Exception { return str.concat ("Caller");} } class…

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