Given the code fragment: String color = "teal"; switch (color) { case "Red": System.out.println("Found Red"); case "Blue": System.out.println("Found Blue"); break; case "Teal"…

The correct answer is E. Found Default. Option E is correct because Java's switch statement uses case-sensitive string comparison, and "teal" (all lowercase) does not match any of the case labels "Red", "Blue", or "Teal" (capital T) - so execution jumps directly to default, printing "Found Default". Why the…

Question

Given the code fragment:
String color = "teal";
switch (color) {
case "Red":
System.out.println("Found Red");
case "Blue":
System.out.println("Found Blue");
break;
case "Teal":
System.out.println("Found Teal");
break;
default:
System.out.println("Found Default");
}
What is the result?

Options

AFound Red Found Default
BFound Teal
CFound Red Found Blue Found Teal
DFound Red Found Blue Found Teal Found Default
EFound Default

How the community answered

(35 responses)

A
11% (4)
B
6% (2)
D
3% (1)
E
80% (28)

Explanation

Option E is correct because Java's switch statement uses case-sensitive string comparison, and "teal" (all lowercase) does not match any of the case labels "Red", "Blue", or "Teal" (capital T) - so execution jumps directly to default, printing "Found Default".

Why the distractors fail:

A is wrong because "Red" never matches "teal", so that case block is never entered.
B is wrong for the same case-sensitivity reason: "Teal" ≠ "teal", so that case is skipped.
C and D are wrong because no case label matches; fall-through only occurs within a switch once a matching case is entered - it cannot chain across unmatched cases.

Memory tip: Think of Java String switches as using .equals(), not equalsIgnoreCase() - if the capitalization isn't pixel-perfect, the case won't fire. When you see a String in a switch, always double-check the exact casing of both the variable's value and the case literals.

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