Given:
```java
1. class MyClass implements Runnable {
2. public int value;
3. public void run() {
4. while (value

Question

Given:
```java
1. class MyClass implements Runnable {
2. public int value;
3. public void run() {
4. while (value < 100) {
5. value++;
6. System.out.println("value: " + value);
7. }
8. }
9. }
10. public class TestThread {
11. public static void main(String[] args) {
12. MyClass mc = new MyClass();
13. Thread a = new Thread(mc);
14. a.start();
15. Thread b = new Thread(mc);
16. b.start();
17. }
18. }
```
What change should you make to guarantee a single order of execution (printed values 1 -100 in order)?

Accepted Answer

A. Line 3: public synchronized void run() {

Answer

B. Line 1: class MyClass extends Thread {

Answer

C. Line 2: public volatile int value;

Answer

D. Line 2: public synchronized int value;

Given: ``java 1. class MyClass implements Runnable { 2. public int value; 3. public void run() { 4. while (value < 100) { 5. value++; 6. System.out.println("value: " + value); 7. } 8. } 9. } 10…

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