Given: class Product { String pname; public Product(String pname) { this.pname = pname; } } and the code fragment: Product p1 = new Product("PowerCharger"); Product p2 = p1…

The correct answer is D. true false. Option D is correct because Product does not override the equals() method, so it inherits Object.equals(), which compares object references (memory addresses), not field values. p2 is assigned directly from p1 - both variables point to the same object in memory - so…

Question

Given:
class Product {
String pname;
public Product(String pname) {
this.pname = pname;
}
}
and the code fragment:
Product p1 = new Product("PowerCharger");
Product p2 = p1;
System.out.println(p1.equals(p2));
Product p3 = new Product("PowerCharger");
System.out.println(p1.equals(p3));
What is the result?

Options

Atrue true
Bfalse true
Cfalse false
Dtrue false

How the community answered

(28 responses)

A
4% (1)
B
4% (1)
C
14% (4)
D
79% (22)

Explanation

Option D is correct because Product does not override the equals() method, so it inherits Object.equals(), which compares object references (memory addresses), not field values. p2 is assigned directly from p1 - both variables point to the same object in memory - so p1.equals(p2) returns true. p3 is created with new, producing a distinct object despite having an identical pname, so p1.equals(p3) returns false.

A (true/true) is wrong because reference equality cannot return true for two separately constructed objects.
B (false/true) and C (false/false) are wrong because p1 and p2 share the same reference, which Object.equals() recognizes as equal.

Memory tip: "No @Override equals = no value comparison." If you don't see equals() overridden in the class, Java falls back to == logic - only the same reference returns true.

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